Question: d e p r e m = 0 . 6 5 v o ( 0 . 4 S D S ) r d C N

deprem=0.65vo(0.4SDS)rd
CN=9.781vo'2:,N1,60f=+N1,60
12
)(%5)=(%35
CRRM75=134-N1,60f+N1,60f135+50[10N1,60f+45]2-1200
rd=1.0-0.00765z,z9.15m
rd=1.174-0.0267z,9.15m30m
deprem=0.65vo(0.4SDS)rd
CN=9.781vo'2:,N1,60f=+N1,60
12
)(%5)=(%35
CRRM75=134-N1,60f+N1,60f135+50[10N1,60f+45]2-1200
rd=1.0-0.00765z,z9.15m
rd=1.174-0.0267z,9.15m30m
Determine the liquefaction potential of the soil profile given in the below figure where max expected earthquake magnitude for the site is 7.3 and Sds=1.1.(Average clay content =%10, groundwater level is 1.5m below ground surface; for clayey soil, sat=20kNm3, for sandy soil in sat=17kNm3; for dry fill sat=16kNm3, for water wat=10kNm3).
Determine the liquefaction potential of the soil profile given in the below figure where max expected earthquake magnitude for the site is 7.3 and Sds=1.1.(Average clay content =%10, groundwater level is 1.5m below ground surface; for clayey soil, sat=20kNm3, for sandy soil in sat=17kNm3; for dry fill sat=16kNm3, for water wat=10kNm3).
d e p r e m = 0 . 6 5 v o ( 0 . 4 S D S ) r d C N

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