D Question 2 4 pts Consider the vector field F(x, y, z) = -kr -ky -kz k ( x2+yz+=2)3/2 : (a2 + +2 2) 3/2 ' ( x2+82+2 2)3/2 = (x'+12+2 2)3/2 ( -, -y, -2) where & is a constant (e.g., an inverse square law force field) and the curve C with parameterization "(t) = (cos(t), sin(t), 0) for 0