d$.$ The heat transfer rate is zero

$28.$ Reducing the equation for an adiabatic tube and shell heat exchanger to its simplest form results in

a$.$ vec$(j{)}^{}=m^{}(hat(h)-h)=m^{}(P-P)$

b$.m_1^{}{h}_2^{}+m_2^{}{h}_2=(m_1^{}+m_2^{})h_4$

c$.(h,h)=(\frac{V^2}{2}-\frac{v^2}{2})$

d$.m_1(h_2-h_n)=m_4^{}(h_2-h_n)$