Question: d V d t = w 1 + w 2 - w ove ral ( 4 - 6 5 ) V d x d t

dVdt=w1+w2-w ove ral (4-65)
Vdxdt=w1(x1-x)+w2(x2-x)
Ccourpound
Assume that volume V remains constant (due to an overflow line that is not shown) and consequently, w=w1+w2. Inlet composition x1 and inlet flow rates w1 and w2 can vary, but stream 2 is pure solute so that x2=1.
The nonlinearities in Eq.4-66 are due to the product terms, w1x1, and so forth. The right side of (4-66) has the functional form f(x,x1,w1,w2). For Step 1 of Fig. 4.5, find the steady-state values of x and w by settings the derivatives of (4-65) and (4-66) equal to zero and substituting the steady-state values. For Step 2, linearize (4-66) about the nominal steady-state values to obtain
 dVdt=w1+w2-w ove ral (4-65) Vdxdt=w1(x1-x)+w2(x2-x) Ccourpound Assume that volume V remains

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