Question: def extract_date(bday): ''' (str) -> int Given a string representing a date in the format YYYY-MM-DD, return the date within the string as an int.
def extract_date(bday): ''' (str) -> int Given a string representing a date in the format YYYY-MM-DD, return the date within the string as an int. >> extract_date('1991-08-02') 2 >> extract_date('1995-12-22') 22 ''' Looking for a solution in python
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