Question: def extract_year(bday: str) -> int: ''' Given a string representing a date in the format DD-MM-YYYY, return the year within the string as an int.

def extract_year(bday: str) -> int: ''' Given a string representing a date in the format DD-MM-YYYY, return the year within the string as an int.

>>> extract_month('02-08-1991') 1991

>>> extract_month('22-12-1995') 1995 '''

python solution no list please

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