def find$\_$paths$($matrix$,$ n$,$ oxygen$\_$capacity$)$:

def dfs$($x$,$ y$,$ path, oxygen$)$:

nonlocal found$\_$paths

if x $<0$ or x $>=$ n or y $<0$ or y $>=$ n or matrix$[$x$][$y$]==\text{'}$O$\text{'}$ or visited$[$x$][$y$]$:

return

oxygen $-=2*$ int$($matrix$[$x$][$y$])$

if oxygen $<0$:

return

visited$[$x$][$y$]=$ True

path.append$($directions$[($x$,$ y$)])$

if $($x$,$ y$)==(0,$ n $-1)$ or $($x$,$ y$)==($n $-1,$ n $-1)$:

found$\_$paths.append$((\text{'}\text{'}.$join$($path$),$ oxygen$))$

for dx$,$ dy in directions.values$()$:

dfs$($x $+$ dx$,$ y $+$ dy$,$ path, oxygen$)$

path.pop$()$

visited$[$x$][$y$]=$ False

directions $=\{$

$(0,1)$: $\text{'}$R$\text{'},$

$(1,0)$: $\text{'}$D$\text{'},$

$(0,-1)$: $\text{'}$L$\text{'},$

$(-1,0)$: $\text{'}$U$\text{'},$

$\}$

visited $=[[$False$]*$ n for $\_$ in range$($n$)]$

found$\_$paths $=[]$

dfs$(0,0,[],$ oxygen$\_$capacity$)$

return found$\_$paths

# Input

n $=$ int$($input$("$Enter the value of n: $"))$

matrix $=[$input$().$strip$()$ for $\_$ in range$($n$)]$

oxygen$\_$capacity $=$ int$($input$("$Enter the oxygen capacity: $"))$

# Finding paths

result $=$ find$\_$paths$($matrix$,$ n$,$ oxygen$\_$capacity$)$

# Output

if not result:

print$("$No path available to reach the destination"$)$

elif not any$($oxygen $>=0$ for $\_,$ oxygen in result$)$:

print$("$No feasible path"$)$

else:

print$("$The available paths are"$)$

for path, $\_$ in result:

print$($path$)$

print$("$The feasible paths with remaining oxygen levels are"$)$

for path, oxygen in result:

if oxygen $>=0$:

print$($f$"\{$path$\}\{$oxygen$\}")$

is this correct?