def validate$\_$float$\_$input$($prompt$)$:

while True:

try:

value $=$ float$($input$($prompt$))$

return value

except ValueError:

print$("$Invalid input. Please enter a valid floating point number."$)$

def main$()$:

names $=[]$

salaries $=[]$

sentinel $=$ 'DONE'

print$("$Enter employee names and salaries. Type 'DONE' when finished."$)$

while True:

name $=$ input$("$Enter employee name $($or DONE to finish$)$: $")$

if name $==$ sentinel:

break

salary $=$ validate$\_$float$\_$input$("$Enter employee salary in thousands $($e$.$g$.,24\mathrm{.}5$ for $24500)$: $")$

names.append$($name$)$

salaries.append$($salary$)$

if len$($salaries$)==0$:

print$("$No valid employee data entered."$)$

return

average$\_$salary $=$ sum$($salaries$)/$ len$($salaries$)$

print$($f$"$

Average Salary: $$\{$average$\_$salary $*1000$:$\mathrm{.}2$f$\}")$

print$("$

Employees with salaries within $$5000$ of the average:"$)$

within$\_$range $=$ False

for name, salary in zip$($names$,$ salaries$)$:

if abs$($salary $-$ average$\_$salary$)<=5$:

print$($f$"$Name: $\{$name$\},$ Salary: $$\{$salary $*1000$:$\mathrm{.}2$f$\}")$

within$\_$range $=$ True

if not within$\_$range:

print$("$No employees have salaries within $$5000$ of the average."$)$

if $\_\_$name$\_\_==\text{'}\_\_$main$\_\_\text{'}$:

main$()$

The code above prints out the average salary and also those within a $5000$ range of it$.$ So I almost have it but the last thing I need is to display every entered employee and their salary added under the text Employee and Salary Entered.