Question: dereference a function pointer is the same as using the function pointer directly as if it's an alias for the pointed function. Similarly, apply

dereference a function pointer is the same as using the function pointer directly as if it's an alias for the pointed function. Similarly, apply \& address-of operator to a function's identifier to fetch the address of the function is the same as using the function's identifier directly.
For example:
int (*fptr)(int, int)= foo; // is the same as int (*fptr)(int, int)=\&foo;
int ham \(=\left({}^{*} f p t r\right)(3,5) ; //\) is the same as int ham \(=\) fptr(3,5);TrueFalse
dereference a function pointer is the same as

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