Design a common-anode 7-segment LED Display Decoder that aims to display the hexadecimal equivalent of a BCD Input.

I posted this question fews days back and someone answered(the photo attached). I am just confused because the 0s are "on" on the truth table but the kmap seems wrong. Can someone enlighten me on this?

Digit g 0 A B co abc ale Oo oo 0001 0 0 1 1 0 0 1 0 0 1 1 1 2 o 0 1 0 0 0 1 0 o 1 0 3 0 0 1 1 0 | 0 1 1 0 4 0 1 0 0 1 0 1 0 5 0 1 0 1 0 1 0 0 1 0 0 6 o 1 0 0 0 0 7 1 1 0 0 8 1 0 0 0 0 0 0 0 0 0 9 1 0 o 1 0 0 0 0 1 0 0 From the above truth table, the Boolean expressions of each output functions can be written as a = F1 (A, B, C, D) = Em (0, 2, 3, 5, 7, 8, 9) b = F2 (A, B, C, D) = {m (0, 1, 2, 3, 4, 7, 8, 9) c = F3 (A, B, C, D) = {m (0, 1, 3, 4, 5, 6, 7, 8, 9) d = F4 (A, B, C, D) = {m (0, 2, 3, 5, 6, 8) e = F5 (A, B, C, D) = {m (0, 2, 6, 8) f = F6 (A, B, C, D) = {m (0, 4, 5, 6, 8, 9) g = F7 (A, B, C, D) = {m (2, 3, 4, 5, 6, 8, 9) Step 3: The third step involves constructing the Karnough's map for each output term and then simplifying them to obtain a logic combination of inputs for each output. K-Map Simplification The below figures shows the k-map simplification for the common cathode seven-segment decoder in order to design the combinational circuit. CD CD AB 00 01 11 10 01 11 10 00 01 11 10 CD 00 AB 00 1 AB 00 00 1 0 1 1 0 1 1 1 1 1 0 01 0 1 1 1 01 1 0 1 0 01 1 1 1 1 Il x 11 X X 11 11 X II 1 1 | x 10 10 11 1 10 1 1 10 1 1 b= B+CD+CD C=B+C+D a = A + C + BD + BD CD 00 01 AB 11 CD 00 10 01 11 10 00 01 11 10 AB 00 CD AB 00 00 1 0 1 1 1 0 0 1 1 0 o 01 0 1 0 1 01 0 0 0 - 1 01 1 1 0 1 1SP - 11 X 11 X X 11 1 IxI IT 10 1 1 x 10 1 0 X 10 1 1 Il d=BD+CD+BCD + BC +A e-BD+CD f=A+CD+BC+BD