Determination of sodium iodide (NaI) in solution (250 mL bottle) * Exactly 5 mL of the drug
Question:
Determination of sodium iodide (NaI) in solution (250 mL bottle)
* Exactly 5 mL of the drug was measured transferred to a volumetric of 50 mL and gauged with Water.
* A 10 mL aliquot of this solution is transferred to an Erlenmeyer flask with 25 mL of AgNO3 0.1M and 3 drops of sulfate indicator solution of ammonium and iron. It was worked at pH strongly acid.
* Excess silver nitrate was valued with potassium thiocyanate (KSCN) 0.2 M until change colored to red.
∙*The titration was repeated with two more aliquots of dissolution.
Results
The consumed volumes of KSCN were: 5.9 mL, 5.8 mL and 5.9 mL.
Based on the above, determine:
a- Calculate the content (mg) of NaI per ml of sample.
b- Calculate the percentage (m / v) of NaI in the formulation.
c- Calculate the grams of NaI in the drug.
Note: For calculations you must calculate the volume of AgNO3 that reacted with the KSCN, then subtract it from the total volume of AgNO3. The volume of AgNO3 obtained is that which reacted with the 10 ml of sample. Then, with it, calculate the molarity of NaI in the solution. From there determine the grams in the 50 ml. Those will correspond to the grams in the 5 ml. Finally with the data you can calculate the mg of NaI per ml of sample, the percentage and the grams.
d. Identify the argentometric method that has been used.