A 10.0-mL sample of potassium iodide solution was analyzed by adding an excess of silver nitrate solution
Question:
KI(aq) + AgNO3(aq) → KNO3(aq) +AgI(s)
If 2.183 g of silver iodide was obtained, what was the molarity of the original KI solution?
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Convert the 2183 g of AgI to mol AgI which is chem...View the full answer
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