Determine the entropy change by adding $100k\frac{J}{k}g$ of heat to saturated liquid water at $100$ kPa in an isobaric process.

a$)$ Determine this value by using the first law to find the change in internal energy, and then interpolating the steam tables to find the change in specific entropy. $($There is work being done$)$

b$)$ Is the process Isothermal?

c$)$ Determine this value by using the change in entropy equation. You may assume the generated entropy is $0.s_{\text{s}\text{y}\text{s}\text{t}\text{e}\text{m}}=s_2-s_1=s_{\text{g}\text{e}\text{n}}+{\displaystyle \underset{1}{\overset{2}{}}}\frac{q}{T}$

d$)$ Under what condition would the assumption from part c hold $($think about the temperature that heat transfer $*$ occurs at$)$