Determine the pressure drop on the hot and cold sides of the regenerator of Problem 5.1...
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Determine the pressure drop on the hot and cold sides of the regenerator of Problem 5.1 having * = 95%. Compute p-pi on each side in percent and determine the total p-p for this regenerator. Generally, design P/P) total is kept below 4 to 5%. Discuss your results. Treat gas as air. Use 0:36910-4 and 0.360 10-4 Pa μ х s for the hot- and cold-fluid sides, respectively, and f = 14/Re: What is the difference between heat capacitance and the heat capacity rate of a fluid? Explain with equations. Determine the pressure drop on the hot and cold sides of the regenerator of Problem 5.1 having * = 95%. Compute p-pi on each side in percent and determine the total p-p for this regenerator. Generally, design P/P) total is kept below 4 to 5%. Discuss your results. Treat gas as air. Use 0:36910-4 and 0.360 10-4 Pa μ х s for the hot- and cold-fluid sides, respectively, and f = 14/Re: What is the difference between heat capacitance and the heat capacity rate of a fluid? Explain with equations.
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ANS WER The pressure drop on the hot side of the regener ator is 0 369 10 4 Pa s and on the cold sid... View the full answer
Related Book For
Principles of heat transfer
ISBN: 978-0495667704
7th Edition
Authors: Frank Kreith, Raj M. Manglik, Mark S. Bohn
Posted Date:
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