Question: Determine whether the sequence converges or diverges. If it converges, find the limit. 2 + 3n2 an = n + 3n 2 + 3n2
Determine whether the sequence converges or diverges. If it converges, find the limit. 2 + 3n2 an = n + 3n 2 + 3n2 To find lim nx n+3n2 by the highest power of n that occurs in the fraction. This is n divide the numerator and denominator Enter an integer or decimal number [more..] After dividing numerator and denominator, we have 2 2 + 3n2 +3 n lim lim n n + 3n2 nx +3 n =
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