Question: Develop body of the even2odd(int n) that takes an integer number as an argument and changes all even digits of the number to odd digits

Develop body of the even2odd(int n) that takes an integer number as an argument and changes all even digits of the number to odd digits by adding one to each odd digit. The method should return the result as an integer number. Develop body of the even2odd(int n) method.

public class Lab5Bonus{

public static void main(String[] args) {

// Sample test case: int n=26540;

System.out.println("n= "+n+", ans= "+even2odd(n));

n=9528;

System.out.println("n= "+n+", ans= "+even2odd(n)); }

/** changes all even digits of argument to odd digits by adding 1 to each digits @param n: a positive integer number @return the result as an integer number */

public static int even2odd(int n) {

int ans=0;

Without use of array and string .

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