Question: DFAs cannot count to an arbitrary value. Use the pumping lemma for regular languages to show that language { EQ w Ea, b}:w=albi is not

DFAs cannot count to an arbitrary value. Use the pumping lemma

DFAs cannot count to an arbitrary value. Use the pumping lemma for regular languages to show that language { EQ w Ea, b}":w=albi is not regular. Here the number of a's in the prefix of w's equals the number of b's in w's suffix

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