Question: This question is asking to proof using Pumping Lemma from Automata theory. Please do not copy previous existing answers. Please use this outline to answer

This question is asking to proof using Pumping Lemma from Automata theory.
Please do not copy previous existing answers.
Please use this outline to answer this question.
Outline of a pumping lemma proof to show the non-regularity of some language A:
Step 1: Assume A is regular. Therefore (by the Pumping Lemma) there exists some number N, which is the "pumping length".
Step 2: Choose a specific string w such that w?A and |w|>=N. Both of these conditions must be explicitly verified for w.
Step 3: Consider an arbitrary factorization of w into xyz such that |y|>=1 and |xy|
Step 4: Create the string w' from w by choosing some value for i>=0. That is, w' = xyiz for some i>=0. Show that w'element of A, no matter how the portions x, y, and z are determined.
Step 5: Conclude that A is not regular since it does not satisfy the Pumping Lemma.
 This question is asking to proof using Pumping Lemma from Automata
Problem #1: These are short answer questions concerning the pumping lemma for regular sets. Assume that we are in the middle of a pumping lemma proof designeed to show that a language is not regular, and that the value "N" and all other preliminaries have been determined. The questions below address specifically the "w" string, chosen in Step 2 of the proof, and the "i" value, chosen in Step 4 of the proof a) Let L -101'ok | i.j.k> 0 and i

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