Question: Differential Equations 5. A 256 pound weight stretches a spring 8 feet. From the equilibrium position, the weight is pushed up 4 inches and then

Differential Equations

5. A 256 pound weight stretches a spring 8 feet. From the equilibrium position, the weight is pushed up 4 inches and then released with an upward velocity of 10 /sec. The weight moves through a damping medium offering a resistance equal to the instantaneous velocity. The weight is driven by an external force equal to 4 sin 573. Set up the differential equation and initial conditions for this problem. Do 1191 solve. (7 points)

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