Discreet maths

Attempt 3: 8 attempts remaining. Put the following statements into order to prove the summation formula P(n) = (Ci-1 7(it) = 1 - n4 ) for all n e N. Put N next to the statements that should not be used. Note that N = {1, 2, 3, ...} is the set of positive integers. 1. The statement is true for n = 1 because in that case, both sides of the equation are 1. 2. Now suppose we have proved the statement P(n) for some n E N. 3. Now suppose we have proved the statement P(n) for all n E N. 4. By adding n + 1 to both sides of P(n), we get 5. Thus, we have proved the statement P(n + 1) = (Zizi i(i+1) -=1- 742) 6. The statement is true for n = 1 because in that case, both sides of the equation are ?. 8. We simplify the right side: 1 - 741 n+1 + (n+1)(n+2) = 1 - n+1 (1 - n42 ) = 1 - -! (n+! ) =1 - n+1 (n+2 ) 1 n+2 9. By adding (ntly(n+2) to both sides of P(n), we get 10. We simplify the right side: 1 - 7 n+1 + (n+1)(n+2) = 1 - n+1 n+1 n42 ) = 1 - - n+1 n+2 ) = 1 - - n+2 11. Zili1 + (n+1)( n+2) = Zio itl =- nit 1 - (n+1) (n+2 ) Submit answer Next item