Do calculations to establish what is the permanent action $($dead load$),$ G$,$ you should use for design of the main floor beams. Assume that we will use pairs of $300$mm x $100$mm sawn timber $($NZ pine$)$ sections for the main beams, $150$mm apart. Consider the main beam between grids A & B along gridline $3$ as being the most heavily$-$loaded beam and note the information regarding floor loads defined in question $1$ is also relevant to this question because the gravity loads can be assumed to be distributed evenly onto the beam by the joists. Combine all dead load contributions and compute a uniformly distributed line load, wG $($in kN$/$m$),$ acting on the main beams.

Note that the main beams along each gridline consist of two solid timber beams, coupled together with blocking $($of negligible weight$)$ to act as a single beam element.

Broken Up into smaller questions

I have already answered $2$a and $2$b but am stuggling with the rest

$2$a$)$ What is the dead load due to the self$-$weight of the main beams? $[$kN$/$m$](3$dp$)$ Answer:$0\mathrm{.}276$

$2$b$)$ What is the dead load due to the self$-$weight of the joists? $[$kN$/$m$](3$dp$)$ Answer:$0\mathrm{.}69$

$2$c$)$ What is the dead load due to other superimposed dead loads, such as flooring, ceiling, and service? $[$kN$/$m$](3$dp$)$

$2$d$)$ Combine all dead load contributions and compute a uniformly distributed line load, wG $($in kN$/$m$),$ acting on the main beams. $[$kN$/$m$](3$dp$)$Figure $5.$ Main member layout proposed for mezzanine floor structure.