Do this question using Java 7 1. Equal Levels Two signals are being generated as part of
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1. Equal Levels Two signals are being generated as part of a simulation. A program monitors the signals. Whenever the two signals become equal at the same time, the frequency is noted. A record is maintained for the maximum simultaneous frequency seen so far. Each time a higher simultaneous frequency is noted, this variable (maxequal) is updated to the higher frequency. Note: • Both signals start at time t-0, but their durations might be different. In this case, the comparison of equality is performed only until the end of the shorter signal. • If both signals have equal frequencies at a given time but the frequency is less than or equal to the current maximum frequency, maxequal, is not updated. The running times of both signals are given, denoted by n and m respectively. During the course of the simulation, how many times is the maxequal variable updated? Example signalOne = [1, 2, 3, 3, 3, 5, 4] signalTwo = [1, 2, 3, 4, 3, 5, 4] VI 3 5 Frequency 1 2 Constraints 4 Time • 1≤n≤105 • 0≤ signalOne[i] ≤ 10⁹ • 1 sm≤105 6 7 0≤ signalTwo[i] ≤ 10⁹ ~ Signal 1 ~ Signal 2 maxequal updated Output-4 Each of the first three signals match and are increasing, so maxequalis updated 3 times to 1, 2 and then 3. At the fourth time, they are not equal. At the fifth, they are equal to 3. Since maxequal contains 3 already, it is not updated. At the sixth time, both signals are equal to 5. This is greater than maxequal = 3, so now maxequal = 5. (maxequal was At the final time, signals are equal to 4. Since 4 is less than maxequal, it is not updated. maxEqual was updated a total of 4 times. Function Description Complete the update Times function in the editor below. update Times has the following parameter(s): int signalOne[n]: the frequencies of the first signal int signalTwo[m]: the frequencies of the second signal Return int: the number of updates updated 4 times) 1. Equal Levels Two signals are being generated as part of a simulation. A program monitors the signals. Whenever the two signals become equal at the same time, the frequency is noted. A record is maintained for the maximum simultaneous frequency seen so far. Each time a higher simultaneous frequency is noted, this variable (maxequal) is updated to the higher frequency. Note: • Both signals start at time t-0, but their durations might be different. In this case, the comparison of equality is performed only until the end of the shorter signal. • If both signals have equal frequencies at a given time but the frequency is less than or equal to the current maximum frequency, maxequal, is not updated. The running times of both signals are given, denoted by n and m respectively. During the course of the simulation, how many times is the maxequal variable updated? Example signalOne = [1, 2, 3, 3, 3, 5, 4] signalTwo = [1, 2, 3, 4, 3, 5, 4] VI 3 5 Frequency 1 2 Constraints 4 Time • 1≤n≤105 • 0≤ signalOne[i] ≤ 10⁹ • 1 sm≤105 6 7 0≤ signalTwo[i] ≤ 10⁹ ~ Signal 1 ~ Signal 2 maxequal updated Output-4 Each of the first three signals match and are increasing, so maxequalis updated 3 times to 1, 2 and then 3. At the fourth time, they are not equal. At the fifth, they are equal to 3. Since maxequal contains 3 already, it is not updated. At the sixth time, both signals are equal to 5. This is greater than maxequal = 3, so now maxequal = 5. (maxequal was At the final time, signals are equal to 4. Since 4 is less than maxequal, it is not updated. maxEqual was updated a total of 4 times. Function Description Complete the update Times function in the editor below. update Times has the following parameter(s): int signalOne[n]: the frequencies of the first signal int signalTwo[m]: the frequencies of the second signal Return int: the number of updates updated 4 times)
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