Question: Does the fact that A* is ``optimally efficient'' mean that A* will never expand more nodes than any other algorithm? Why any node in the
Does the fact that A* is ``optimally efficient'' mean that A* will never expand more nodes than any other algorithm?
Why any node in the frontier with f(n) < f^*(n) (the cost of the optimal solution path) will eventually be selected for expansion by A*?
Is it true that all admissible heuristics are equal in the sense that A* will search the states in the same order no matter what the heuristic is?
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