a) Suppose that there are 3.0 x 107 radon atoms (71/2 = 3.83 days or 3.31...

 

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a) Suppose that there are 3.0 x 107 radon atoms (71/2 = 3.83 days or 3.31 x 105 s) trapped in a basement. i. How many radon atoms remain after 31 days? ii. Find the activity just after the basement is sealed against further entry of radon? iii. Find the activity 31 days later? b) Two deuterium atoms (2H) react to produce tritium (2H) and hydrogen (2H) according 111 to the following reaction: What is the energy (in MeV) released by this deuterium-deuterium reaction? a) Suppose that there are 3.0 x 107 radon atoms (71/2 = 3.83 days or 3.31 x 105 s) trapped in a basement. i. How many radon atoms remain after 31 days? ii. Find the activity just after the basement is sealed against further entry of radon? iii. Find the activity 31 days later? b) Two deuterium atoms (2H) react to produce tritium (2H) and hydrogen (2H) according 111 to the following reaction: What is the energy (in MeV) released by this deuterium-deuterium reaction?

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A i ANSWER There are 6 9 x 101 0 atoms remaining after 31 days EXPLANATION The number of rad on atoms remaining after 31 days can be calculated using the half life of rad on The half life of rad on is ... View the full answer