Dog Data

In each question below, you will define a new table based on the following tables.

CREATE TABLE parents AS SELECT "abraham" AS parent, "barack" AS child UNION SELECT "abraham" , "clinton" UNION SELECT "delano" , "herbert" UNION SELECT "fillmore" , "abraham" UNION SELECT "fillmore" , "delano" UNION SELECT "fillmore" , "grover" UNION SELECT "eisenhower" , "fillmore"; CREATE TABLE dogs AS SELECT "abraham" AS name, "long" AS fur, 26 AS height UNION SELECT "barack" , "short" , 52 UNION SELECT "clinton" , "long" , 47 UNION SELECT "delano" , "long" , 46 UNION SELECT "eisenhower" , "short" , 35 UNION SELECT "fillmore" , "curly" , 32 UNION SELECT "grover" , "short" , 28 UNION SELECT "herbert" , "curly" , 31; CREATE TABLE sizes AS SELECT "toy" AS size, 24 AS min, 28 AS max UNION SELECT "mini" , 28 , 35 UNION SELECT "medium" , 35 , 45 UNION SELECT "standard" , 45 , 60;

Your tables should still perform correctly even if the values in these tables change. For example, if you are asked to list all dogs with a name that starts with h, you should write:

SELECT name FROM dogs WHERE "h" <= name AND name < "i";

Instead of assuming that the dogs table has only the data above and writing

SELECT "herbert";

The former query would still be correct if the name grover were changed to hoover or a row was added with the name harry.

Q1: Size of Dogs

The Fdration Cynologique Internationale classifies a standard poodle as over 45 cm and up to 60 cm. The sizes table describes this and other such classifications, where a dog must be over the min and less than or equal to the max in height to qualify as a size.

Create a size_of_dogs table with two columns, one for each dog's name and another for its size.

-- The size of each dog CREATE TABLE size_of_dogs AS SELECT "REPLACE THIS LINE WITH YOUR SOLUTION"; -- Example: SELECT name FROM size_of_dogs WHERE size="toy" OR size="mini"; -- Expected output: -- abraham -- eisenhower -- fillmore -- grover -- herbert