Draw a square with a Pentagram hole!$$

The $33$ square extends from $0\mathrm{.}7$ to $2\mathrm{.}3$ on the X axis and from $0\mathrm{.}3$ to $2\mathrm{.}7$ on the Y axis.$$

Keep the X and Y arrays named$$xp and yp$,$ respectively.

For your convenience, your Pentagram code from $1\mathrm{.}6$ is copied below.

Do not forget to separate the pentagram and the square with None.

Draw the square using negative orientation $($because the orientation of the Pentagram is positive$).$

Code from $1\mathrm{.}6$:

import matplotlib.pyplot as plt

xp $=[0,0\mathrm{.}81,1\mathrm{.}62,1\mathrm{.}31,2\mathrm{.}12,1\mathrm{.}12,0\mathrm{.}81,0\mathrm{.}5,-0\mathrm{.}5,0\mathrm{.}31,0]$

yp $=[0,0\mathrm{.}59,0,0\mathrm{.}95,1\mathrm{.}54,1\mathrm{.}54,2\mathrm{.}49,1\mathrm{.}54,1\mathrm{.}54,0\mathrm{.}95,0]$

plt$.$axis$("$equal$")$

plt$.$axis$("$off$")$

plt$.$fill$($xp$,$ yp$)$

plt$.$show$()$