Question: dz dz Q4. The differential equation for components A, B and C are given in equation (1): dCA 1-2kcas, u da - +kC s u

 dz dz Q4. The differential equation for components A, B and

dz dz Q4. The differential equation for components A, B and C are given in equation (1): dCA 1-2kcas, u da - +kC s u dcc =0 (Eq. 1) C, is the concentration on the surface, expressed as the kmol of a species per volume of the catalyst, The equation (2) relates the rate of mass transfer to the catalyst to the rate of reaction. kma(CA - CAS) - koks (Eq. 2) km, a and k are mass transfer coefficient (m/s), surface area exposed per volume of the reactor (m/m), and rate of reaction rate constant (m/kmol s). This problem combines ordinary differential equations with nonlinear algebraic equations. Use the following initial conditions: CA(0) - 2 kmol/m2.C() - 0.CO) - 2 kmol/m3 (Eq. 3) and we take u = 0.5 m/s, k = 0.3 m/kmol s, kma = 0.2 and the total reactor length as z = 2.5 m. [5 Marks) dz dz Q4. The differential equation for components A, B and C are given in equation (1): dCA 1-2kcas, u da - +kC s u dcc =0 (Eq. 1) C, is the concentration on the surface, expressed as the kmol of a species per volume of the catalyst, The equation (2) relates the rate of mass transfer to the catalyst to the rate of reaction. kma(CA - CAS) - koks (Eq. 2) km, a and k are mass transfer coefficient (m/s), surface area exposed per volume of the reactor (m/m), and rate of reaction rate constant (m/kmol s). This problem combines ordinary differential equations with nonlinear algebraic equations. Use the following initial conditions: CA(0) - 2 kmol/m2.C() - 0.CO) - 2 kmol/m3 (Eq. 3) and we take u = 0.5 m/s, k = 0.3 m/kmol s, kma = 0.2 and the total reactor length as z = 2.5 m. [5 Marks)

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