Question: - E 1 - 8 which tends to 0 as e - 0 since a > 0. The residue at z = -1, with our



![dx + dx = [1 - (2xi(-1)] dx o 1+x 100 1+x](https://s3.amazonaws.com/si.experts.images/answers/2024/06/66652aad370fa_09366652aad25561.jpg)
- E 1 - 8 which tends to 0 as e - 0 since a > 0. The residue at z = -1, with our choice of branch for z"-1, equals el(@-1). Hence xu-1 2al(a-1) dx + dx = [1 - (2xi(-1)] dx o 1+x 100 1+x o 1+ x = 2niel*(@-1) or [e-in(a-1) _ gin(a-1)] dx = 2xi, 1+x that is, dx = when 0
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