Question: .- E ForA = 1i + -4j + -6k, 5 = -2i + 2j + 9k, and c = 7i + -sj + -8k, nd

.- E ForA = 1i + -4j + -6k, 5 = -2i + 2j + 9k, and c = 7i + -sj + -8k, nd c - (A-B). Submit Answer Tries 0/10 0 a 1a. A 13.2kg block is dragged over a rough, horizontal surface by a 70.7N force acting at 16.3 degrees above the horizontal. The block is displaced 4.98m, and the coefcient of kinetic friction is 0.304. Find the work done by the 70.7N force. Submit Answer Tries 0/10 1b. Find the work done by the normal force. Submit Answer Tries 0/10 1c. What work does the gravitational force do on the block? Submit Answer Tries 0/10 1d. How much energy is lost due to friction? Submit Answer Tries 0/10 1e. Find the total change in the block's kinetic energy. Submit Answer Tries 0/10 0 a 3. Calculate the scalar product of the vectors in the gure below. Assume 91 = 110, 62 = 136, F = 33.8N and v = 17.0cm/5. Submit Answer Tries 0/10 V V 0 a A force F = (4.07x i + 2.91y j)N, where X and y are in metres, acts on an object as it moves in the x direction from the origin to x = 5.18m. Calculate the work done on the object by the force
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