Question: ( e ) points n = 1 ( 2 n + 1 ) ! n n ( f ) points n = 1 ( -

(e) pointsn=1(2n+1)!nn
(f) pointsn=1(-1)nn2+1n3
(g)(5 points)n=132n5n
( e ) points n = 1 ( 2 n + 1 ) ! n n ( f ) points

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