Question: e y x x y 2 - x = c , y ' = x 2 ( 1 - y 2 ) y e y

eyxxy2-x=c,y'=x2(1-y2)yeyxx(eyx2x2y). Determine the solution with y(1)=0 equals zero
e y x x y 2 - x = c , y ' = x 2 ( 1 - y 2 ) y e y

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