EGG 131L, Lab 8 Manual, 90 points Alcohol D = WSA - WSL 70 - 63 7 8 =0. 875 D=. 87 9 1cm3 WSA - WSW - 70 - 622. Refer to Lab 8 (a) A sinker of 4 Oz is weighed to be 3 OZ in water. How many Oz will it weigh in the alcohol used in Lab 8? (15 points) (b) An iceberg with a cuboid shape is floating on the sea. The density of ice is 917 kg/m', and the density of seawater is 1030 kg/m'. If the volume of the iceberg under the sea is 10 cubic miles and the height of the iceberg above the sea is 100 ft, how many acres is the horizontal area of the iceberg? (20 points)( aj Let the leadum of sinker be V. The divalue of displaced water will be V. The weight of displaced water will be ww = VP Ng p = 1050 kg / m 3 = 10ODV Ng = looOV X 35. 274 0Z . . Since 1 kg = 35 . 274 02 = 35974 V 02. The weight of sinker in air will be equal to weight of sinker in water plus weight of displaced water , so weight of sinkers in air I weight of sinker in water + weight displaced water 4 = 3+ 35274V DY 1 = 35274V V 2 35274 when sinker is deroped in alcohol it diplace alconal of volume v. se. weight of sinkers in alcohol is given as hisa = weight of sinker in aww - weight of dispace allchal 4 -( VP ) x 35- 274 = 4 - 35274 - x 870x35.274 ( from Lab 8 manual ) = 4 - 0.87 lake = 3. 13 0Z