Question: EH 0 8 4 . ( CH 3 CHO ) - ki CH 3 CHO + CH 3 + + CHO * k 2 CH

EH08
4.(CH3 CHO)-ki CH3CHO + CH3++CHO * k2 CH3CHO + CH3+> CH4+ CH3CO + k3 CH3CO * CO + CH3* k4 CH3*+CH3** C2H6*., CHO *. d[CH4]<<([CH3CHO])3/23/2 K d[CH4)= K ([CH2CHO])3/2[C2H6]=-2k4[CH2*]

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