ELECTRIC CIRCUITS7) please help!! I can't get the last part!!

wFour capacitors are arranged in a circuit as shown in the figure. ::f The capacitors have the values C; = 22.5 uF, C; = 45.5 pF, g C3 = 50.5 pF, and C; = 40.5 pF. The power supply is at voltage V' = 32.5 V. g v c, C C, What is the equivalent capacitance C,, of the circuit in microfarads? Ceq = 12.9 pE What is the charge @, on capacitor C;? 0 = 5 x10~ e 'What is the potential difference V3 across capacitor C3? V3 = 4.6 Vv 'What is the potential energy Uy stored in capacitor C4? Incorrect I. Four capacitors are arranged in the circuit shown in the figure. The capacitors have the (a) What is the equivalent capacitance of the circuit? Here we want to use Cpupqiel Ci1+Cs+C3+...and 1/Ciepies = 1/C1+1/C32+1/C3 + ... to reduce the circuit to it's equivalent capacitance (b) What is the charge on capacitor C3? Here we want to use AV, = QQ/C. Note that the charge on capacitor 1 and capacitor 2 must be equal (Q, = Q-). (c) What is the potential difference across capacitor Cy?Here vou can use the Kirchhoff Loop Rule to solve for V3. (d) What is the potential energy stored in capacitor C4;?You know that V5 = V; be- cause those two capacitors are in parallel, then you can use AU, = :Q(AV) = 1C(AV)? = 1@Q?%/C