Eliminate the parameter $to$ find a Cartesian equation $of$ the following curve:

$x=25t^2,y=-8t^3$

Choose the answer from the following:

$x=25y^{\frac{2}{3}}$

$x=6\mathrm{.}25y^{\frac{3}{2}}$

$x=25y^{\frac{3}{2}}$

$x=6\mathrm{.}25y^{\frac{2}{3}}$