encrypt the plaintext message "CSULA"

(B) Use Vigenre Square by starting from the third substitution row (i.e., labeled 'C' row) to obtain the ciphertext. (C) Use the ASCII table as below (For example, 't' = 74 in Hex or 1110100 in binary.) to find the binary number of the plaintext, then use transposition key pattern: 1->4, 2->7, 3->1, 4->5, 5->6, 6->2, 7->3 to obtain the ciphertext. Note: the block size is 7. (D) Use a secret key V to encrypt each letter of the plaintext via XOR to find the ciphertext. MSD LSD 0 1 5 6 ow 0 NUL DLE P space 1 1 SOH DC1 1 Q a 9 2. STX DC2 2 B R b r 3 ETX DC3 # 3 S S 4 EOT DCA $ 4 D T d t 5 ENQ NAK % 5 E U e u 7416 6 ACJ SYN & B F V f V 111 0100 7 BEL ETB 7 G w g W 8 BS CAN ( H h 9 HT EM ) 9 1 Y i A LF SUB J Z j Z B VT ESC K [ k FF FS L 1 D CR GS M } E SO RS N n F S US ? 0 0 DEL