$\backslash$end$\{$array$\}]$

$5$

b$)$ The overall Nusselt number for this case can be calculated by using a correlation

$\frac{?}{\text{b}\text{a}\text{r}}({)}_d=1\mathrm{.}86(R{e}_{d}Pr{)}^{\frac{1}{3}}(\frac{d}{L}{)}^{\frac{1}{3}}(\frac{}{{}_w}{)}^{0\mathrm{.}14}$

where ${}_w$ is the water viscosity evaluated at the tube wall temperature $T_s=355$ K $,$ d is the tube diameter, and L is the tube length. Calculate the water temperature at the tube outlet by using an assumption of $T_o=347K.$ What is the difference between the assumed outlet water temperature and your calculated result? $(25$ points$)$

$\mathrm{.}14$