Question: end { array } ] a n = H n + 1 n = H n + 1 = H ( n - 2

\end{array}]
an=Hn+1
n=Hn+1
=H(n-2+1)+1
=H-2+H+1
=H(n-2+1)+1
=Hn-2+H+1
thod.
 \end{array}] an=Hn+1 n=Hn+1 =H(n-2+1)+1 =H-2+H+1 =H(n-2+1)+1 =Hn-2+H+1 thod.

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