The lengths (in mm) of a random sample of 10 herring (Pomolobus aestivalis) have sample mean...

 

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The lengths (in mm) of a random sample of 10 herring (Pomolobus aestivalis) have sample mean = 53.86 mm. Suppose that the population standard deviation is c = 5 mm, and assume that the lengths are normally distributed. a. Is there evidence that the mean length for this species of herring is less than 58mm? i. Write out appropriate null and alternative hypotheses using symbols ii. Test the hypothesis using significance level a = 0.01 (calculate z, get a p-value, use the p-value to make a decision). iii. State your conclusions in plain language. iv. If your conclusion in the previous part was wrong, what type of error would this be? b.[2] Would your decision in part (a) be different if instead a significance level of a = 0.05 had been used? Why? The lengths (in mm) of a random sample of 10 herring (Pomolobus aestivalis) have sample mean = 53.86 mm. Suppose that the population standard deviation is c = 5 mm, and assume that the lengths are normally distributed. a. Is there evidence that the mean length for this species of herring is less than 58mm? i. Write out appropriate null and alternative hypotheses using symbols ii. Test the hypothesis using significance level a = 0.01 (calculate z, get a p-value, use the p-value to make a decision). iii. State your conclusions in plain language. iv. If your conclusion in the previous part was wrong, what type of error would this be? b.[2] Would your decision in part (a) be different if instead a significance level of a = 0.05 had been used? Why?

Answer rating: 100% (QA)

a i Null hypothesis H 58 mm Alternative hypothesisH 58 mm ii The zscore is calculated as z x n where x is the sample mean 5386 mm is the hypothesized ... View the full answer