[ Entered | Answer Preview 2*pl'r'[r*asin[r}-r-r'aslnf]] 21:!\"(3' sin-1 (1*) - r' - r sin-1011)) [1 point) If the some y = x), a 5 x 5 b, is rotated about the horizontal llne )1 = c, wherex) S c, than one can prove that a formula forthe area ofthe resulting surface is b S =/ 2gp: f[x)]1l)1 + [f'{x)]3ct. nd the area ofthe surface generated by rotating the circle 1:3 + 3:2 = r2 about the line 3.! = r. Surface area = 2pi[r}[rarcsin[r} - r -{rarcsin[]}} cheg said it should be pi*r\"2*[pi-2] please help don't I-rnow why both are wrong