Entered Answer Preview Result Message (x - 5)20 [(x-5)^(2*n)]/[(5^n)*(n!)] incorrect Your expression generates the wrong value for terms 1,2,3,4 5" (n!) incorrect At least one of the answers above is NOT correct. (1 point) Consider the series L an = (x- 5)2 4 (x - 5)4 (x - 5)6 (x - 5)8 + + + ... 5 . 2! 25 - 3! 125 . 4! Find an expression for an . an = (x-5)^(2n)/(5^(n)(n!)) In the summation formula n starts at n = no . What is your starting index no ? no (Note that because the validity of either of your answers depends on the other, if you enter only one, both will be marked wrong.)Entered Answer Preview Result k [(-3)^k]'e*([x+(1/3)]^k) (-3) *e( x + incorrect The answer above is NOT correct. (1 point) Use sigma notation to write the Taylor series about x = x, for the function. e-3*, xo = -- Taylor series = M: (-3)^(K)e(x+(1/3))^k k=0(1 point) How many years would it take your money to double: (a) At 10% interest compounded yearly. 7.02 years. (b) At 10% interest compounded weekly. years and weeks. (c) At 10% interest compounded continuously. years