Eour secular equations are generated.

$0=(-)c_1+c_2+00+0$

$0=c_1+(-)c_2+c_3+0$

$0=0+c_2+(-)c_3+c_4$

$0=0+0+c_3+(-)c_4$

There are four solutions for the energy.

${}_1=+1\mathrm{.}6180$

${}_2=+0\mathrm{.}6180$

${}_3=-0\mathrm{.}6180$

${}_4=-1\mathrm{.}6180$

Eour wave functions are generated.

${}_1=0\mathrm{.}3717p_1+0\mathrm{.}6015p_2+0\mathrm{.}6015p_3+0\mathrm{.}3717p_4$

${}_2=0\mathrm{.}6015p_1+0\mathrm{.}3717p_2-0\mathrm{.}3717p_3-0\mathrm{.}6015p_4$

${}_3=0\mathrm{.}6015p_1-0\mathrm{.}3717p_2-0\mathrm{.}3717p_3+0\mathrm{.}6015p_4$

${}_4=0\mathrm{.}3717p_1-0\mathrm{.}6015p_2+0\mathrm{.}6015p_3-0\mathrm{.}3717p_4$

Which energy level, ${}_i,$ is the lowest energy level?

Which orbital, ${}_i,$ is represented below. Explain.