Equations: E = kq Q = K = 9 x 10 9 Nm2/C2 Fe = k . 21 02 7-2 Two charged particles have an electrostatic force of Fe when placed a distance of d meters apart. If the distance between the charged particles was increased to 4d meters, what would be the electrostatic force between the particles? O 1/4 Fe O 1/16 Fe 8 Fe 4 FeEquations: E = kq K = 9 x 10 9 Nm2/C2 Fe = k . 21 02 Three metal spheres are placed beside each other. Sphere A has a charge of +4Q, Sphere B has a charge of -2Q and Sphere C has a charge of +2Q. Sphere A touches Sphere B and separates. Then, Sphere A touches Sphere C. What is the final charge of Sphere A? O -1.5Q O +3Q O -3Q O +1.5Q"'* k=9x109Nm2/02 rifle-"1\"?2 . _ _5_ Equations. E Q r2 r2 When a charged plastic rod is brought near a neutral aluminum can (without touching it), the can begins to move towards the charged rod. The can's attraction arises from a it's conductive charge friction between the rod and the can polarization m induction charging Equations: E = F kq k = 9 x 109 Nm2/C2 Fe = k . 21 Q2 7-2 A penny has gained an electrical charge of +3 uC. This happened because the penny- Gained Electrons. Gained Protons. O Lost Electrons. O Lost Protons.- . _E_"_'1 Equations. E _q 12 k = 9x 10 9 Nm2/C2 Fe = k 32102 N: Q/e e = fundamental charge = 1.6x 10 '19 T2 A small neutral metal sphere has had 5 x 1013 electrons removed from the sphere. What is the new charge of the metal sphere? 5x1013 0 8x10'6 0 3.125x1032 ' D Equations: E = 5 = k = 9x109 Nm2/C2 Fe = k - 0'02 N= Q/e e = fundamental charge = 1.6x10'79 Q 2 r2 Asmall neutral metal sphere has had 5 x 1013 electrons removed from the sphere. If the electrons removed from the sphere were placed on a second neutral sphere located 1.5 meters away, what would be the electrostatic force between the spheres? rx5X1w3N m 64x1o\"~ O -.256 N O -.576 N Equations: E = g = :g k = 9x 10 9 Nm2/C2 Fe = k .0120: N: Q/e e = fundamental charge = 1.6x 10 "9 Are the electric field lines drawn correctly? a. yes 0 b. no, field lines do not cross a. no, field lines enter positive charges b. yes a. no b. no a. yes \\ J b. yes Equations: E = kq - 2 K = 9 x 10 9 Nm2/C2 Fe = k . 21 02 7-2 N= Q/e e = fundamental charge = 1.6 x 10 -19 What is the magnitude of the electric field due to a 2.0 x 10" C charge at a point 0.50 m away? 1.6 x 10 -8 N/C 8x 10 9 N/C 144 N/C 0 72 N/CEquations: E = E _ kq Q K = 9 x 10 9 Nm2/C2 Fe = k . 21 02 N= Q/e e = fundamental charge = 1.6 x 10 -19 If q1 has a charge of -8C, what is the charge of q2? 91 92 O -2 C O +2 C 0 -4C 0 4 CEquations: E = g = g k = 9x 10 9 Nm2/C2 Fe = k - 0:32 N: Q/e e = fundamental charge = 1.6 x 10 "9 A charge of -3.0 x 10 '5 C is located at a place where there is an electric field that points due east and has a magnitude of 20,000 N/C. What are the magnitude of the force acting on the charge? A -255 N m +0.2997 N -.6 N O4N