Error Detection Code (show all the details/work) Suppose the information portion of a packet (D in Figure 6.3) contains 10 bytes as follows: D: 01001100 01101001 01101110 01101011 00100000 01001100 01100001 01111001 01100101 01110010 a. Suppose an even parity scheme is being used. Provide detail comments on how this parity is computed and then compute a parity bit for each row. b. Now consider an odd parity scheme, provide detail discussion on how this parity is computed and compute the 2D parity bits for D. What would the value of the field containing the parity bits be for the case of a two-dimensional parity scheme? Assume the bits in D are divided into 10 rows and 8 columns (i.e., each byte is a row).