Question: (8) Calculate 46 for the ions in solution in Problem # 7 above. a) - 61 kJ/md 6) -71 kJ/mol c) - 81 kJ/mol

Calculate 4Go for the ions in solution in problem #7 above. a) – 61 ku sed 6)-71 kJ/mol ) -81 kJ/mol


reactions for asolution (7) Here of are a half ions @ 25°C 3+ Fe (aq) to te Cext te Feet Ce = 0.770 E cathode a 1.610 first

Calculate 4Go for the ions in solution in problem #7 above. a) – 61 ku sed 6)-71 kJ/mol ) -81 kJ/mol  
 

(8) Calculate 46 for the ions in solution in Problem # 7 above. a) - 61 kJ/md 6) -71 kJ/mol c) - 81 kJ/mol Hint a) Here are of ions @ 25C a half reactions for 3+ Fe (ag) Cet te Ce E cell 14 2x10 = K 2+ te Fe First calculate. 24 b) 2x10 = K a solution. 0.77v E cathole = 1.61V Then, calculate K. 34 anode 34 e) 2x10 = = K (8) Calculate 46 for the ions in solution in Problem # 7 above. a) - 61 kJ/md 6) -71 kJ/mol c) - 81 kJ/mol

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