Evaluate each definite integral. Some integrals may be improper. If an improper integral diverges, say so$.$

$($a$){\displaystyle \underset{0}{\overset{}{}}}\frac{dx}{\sqrt[\phantom{2}]{x}+x\sqrt[\phantom{2}]{x}}$

$($f$){\displaystyle \underset{0}{\overset{1}{}}}\frac{(d)x}{\sqrt[\phantom{2}]{1-x^2}}$

$($b$){\displaystyle \underset{-}{\overset{-1}{}}}\frac{e^{\frac{1}{x}}}{x^2}dt$

$($g$){\displaystyle \underset{0}{\overset{\frac{}{2}}{}}}si{n}^{3}co{s}^{2}d$

$($c$){\displaystyle \underset{0}{\overset{e}{}}}\frac{1}{1-x}dx$

$($h$){\displaystyle \underset{-1}{\overset{1}{}}}\frac{dx}{x^2-2x}$

$($d$){\displaystyle \underset{\sqrt[\phantom{2}]{2}}{\overset{2}{}}}\frac{1}{x\sqrt[\phantom{2}]{x^2-1}}dx$

$($i$){\displaystyle \underset{1}{\overset{}{}}}\frac{lnx}{x^4}dx$

$($e$){\displaystyle \underset{1}{\overset{}{}}}\frac{arctanx}{x^2+1}dx$

$($j$){\displaystyle \underset{0}{\overset{81}{}}}\frac{2^{\sqrt[\phantom{2}]{x}}}{\sqrt[\phantom{2}]{x}}dx$