Question: Evaluate the definite integral 5 6 ( d d t 4 + 3 t 4 2 ) d t using the Fundamental Theorem of Calculus.

Evaluate the definite integral
56(ddt4+3t42)dt
using the Fundamental Theorem of Calculus.
You witl need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
56(ddt4+3t42)dt
=
Evaluate the definite integral 5 6 ( d d t 4 + 3

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