Question: Evaluate the definite integral [(x^3 - 2x^2 + 3x-4)dx from x=1 to x=3.

Evaluate the definite integral [(x^3 - 2x^2 + 3x-4)dx from x=1 to

Evaluate the definite integral [(x^3 - 2x^2 + 3x-4)dx from x=1 to x=3.

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