Evaluate the following limit$.$

$\underset{x0}{lim}\frac{secx-1}{ta{n}^{2}x}$

Change the given indeterminate form into a determinate form. Choose the correct answer below.

A$.\frac{sinx}{cotx-1}$

B$.\frac{cotx-1}{sinx}$

C$.secx+1$

D$.\frac{1}{secx+1}$

Evaluate the limit$.$ Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

A$.\underset{x0}{lim}\frac{secx-1}{ta{n}^{2}x}=,($Simplify your answer.$)$

B$.$ The limit does not exist and is neither $$ nor $-.$