Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) $$ \begin{aligned} g(x) &=\frac{3-x}{3+x} ; \quad g(2), g(-3), g\left(\frac{1} {2} ight), g(a), g(a-3), g\left(x^{2}-3 ight) g(2) &=\square W 8(-3) &=\square W g\left(\frac{1}{2} ight) &=\square g(a) &=\square W &(a-3) &=\square g\left(x^{2}-3 ight) &=\square \end{aligned} $$ Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) $(-6)=$ $f(-5)=$ $f=$ $f(1) =$ $f\left(x^{2} ight)=$ $x eg 0$ $f\left(\frac{1}{x} ight)=$ CS.SD. 123